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16x^2-10.3x=2
We move all terms to the left:
16x^2-10.3x-(2)=0
a = 16; b = -10.3; c = -2;
Δ = b2-4ac
Δ = -10.32-4·16·(-2)
Δ = 234.09
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10.3)-\sqrt{234.09}}{2*16}=\frac{10.3-\sqrt{234.09}}{32} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10.3)+\sqrt{234.09}}{2*16}=\frac{10.3+\sqrt{234.09}}{32} $
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